14x^2-50x-24=

Solution for 14x^2-50x-24= equation:

14x^2-50x-24=

We move all terms to the left:

14x^2-50x-24-()=0

We add all the numbers together, and all the variables

14x^2-50x=0

a = 14; b = -50; c = 0;
Δ = b2-4ac
Δ = -502-4·14·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-50}{2*14}=\frac{0}{28}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+50}{2*14}=\frac{100}{28}
=3+4/7
$